Python Armstrong Number
Python3 ExamplesIf annn-digit positive integer is equal to its digits'nsum of powers, then the number is called an Armstrong number.1^3 + 5^3 + 3^3 = 153。
Armstrong numbers within 1000: 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407.
The following code is used to check whether the number entered by the user is an Armstrong number:
Example (Python 3.0+)
# Filename : test.py
# author by : www.example.com
# Python checks whether the number entered by the user is an Armstrong number
# Get the number entered by the user
num = int(input("Please enter a number:"))
# Initialize variable sum
sum = 0
# Exponent
n = len(str(num))
# Check
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** n
temp //= 10
# Output result
if num == sum:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
Executing the above code produces the following output:
$ python3 test.py 请输入一个数字: 345 345 不是阿姆斯特朗数 $ python3 test.py 请输入一个数字: 153 153 是阿姆斯特朗数 $ python3 test.py 请输入一个数字: 1634 1634 是阿姆斯特朗数
Get Armstrong numbers within a specified range
Example (Python 3.0+)
# Filename ：test.py
# author by : www.example.com
# Get user input numbers
lower = int(input("Minimum value:"))
upper = int(input("Maximum value:"))
for num in range(lower,upper + 1):
# Initialize sum
sum = 0
# Exponent
n = len(str(num))
# Check
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** n
temp //= 10
if num == sum:
print(num)
Executing the above code produces the following output:
最小值: 1 最大值: 10000 1 2 3 4 5 6 7 8 9 153 370 371 407 1634 8208 9474
In the above example, we output the Armstrong numbers between 1 and 10000.
Other extensions