Java Examples - Chained Exception
Java ExamplesThe following example demonstrates using multiple catch blocks to handle chained exceptions:
Main.java file
public class Main {
public static void main (String args[])throws Exception {
int n=20,result=0;
try{
result=n/0;
System.out.println("The result is:"+result);
}
catch(ArithmeticException ex){
System.out.println("Arithmetic exception thrown:"+ex);
try {
throw new NumberFormatException();
}
catch(NumberFormatException ex1) {
System.out.println("Manually throw chained exception:"+ex1);
}
}
}
}
The output of the above code is:
发算术异常: java.lang.ArithmeticException: / by zero 手动抛出链试异常 : java.lang.NumberFormatExceptionOther extensions