C Exercise Example 17
Title:Input a line of characters, and respectively count the number of English letters, spaces, digits, and other characters.
Program analysis:Use the while statement, with the condition that the input character is not '\n'.
Example
// Created by www.example.com on 15/11/9.
// Copyright © 2015 Example. All rights reserved.
#include <stdio.h>
int main() {
char c;
int letterCount = 0, spaceCount = 0, digitCount = 0, otherCount = 0;
printf("Please enter some characters:\n");
while ((c = getchar()) != '\n') {
if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z')) {
letterCount++;
} else if (c >= '0' && c <= '9') {
digitCount++;
} else if (c == ' ') {
spaceCount++;
} else {
otherCount++;
}
}
printf("Letters = %d, Digits = %d, Spaces = %d, Others = %d\n", letterCount, digitCount, spaceCount, otherCount);
return 0;
}
The output of the above example is:
请输入一些字母： www.example.com 123 字母=12,数字=3,空格=1,其他=2other extensions